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Winetalk.com
11-18-2004, 07:09 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?

grimm
11-18-2004, 07:18 AM
there are two answers to this problem.

ifit is a trick question, the fact that you said "a goat" would imply one goat, which if already revealed would mean your options are better. but if there was a goat behind the door you opened (not specified) then your odds would be 100% that the third door would hold a BMW, since both goats would be revealed.

so that argument is all semantics.

Say the door you opened was goatless, then it comes down to odds.

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take

Winetalk.com
11-18-2004, 07:22 AM
gotta be my bad English...

there are goats behind 2 out of 3 doors

you haven't opened the door,
you only indicated the door which you would like to open.

sorry for misunderstanding the first time around

Winetalk.com
11-18-2004, 07:23 AM
Originally posted by grimm@Nov 18 2004, 07:19 AM

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take
bzzz...wrong!

grimm
11-18-2004, 07:24 AM
oh shit i missed it completely.... one sec.

there is nothing specifying that a goat cannot be behind the same door as a goat.

so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem

now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds.



fucking trick questions

grimm
11-18-2004, 07:26 AM
Originally posted by grimm@Nov 18 2004, 04:25 AM
oh shit i missed it completely.... one sec.

there is nothing specifying that a goat cannot be behind the same door as a goat.

so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem

now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds.



fucking trick questions
goat cannot be behind the same door as another goat, or the BMW, but that doest change the outcome. the revealing of the goat took us to 1/3 anyway, if and only if there were two goats in there, her odds would go to 100% choice as she had seen both goats and an empty door, so that doesnt matter.

anyway her odds are better

Lee
11-18-2004, 07:28 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:10 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?
You have an equal chance by opting to open the other door.

You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW.

Winetalk.com
11-18-2004, 07:28 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!

grimm
11-18-2004, 07:30 AM
Originally posted by Lee+Nov 18 2004, 04:29 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 04:29 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:10 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?
You have an equal chance by opting to open the other door.

You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW. [/b][/quote]
you missed the possibility of two goats being behind any door, nor the combinations of goat +BMW, or goat + goat + BMW

Lee
11-18-2004, 07:30 AM
Originally posted by grimm+Nov 18 2004, 04:31 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 04:31 AM)</td></tr><tr><td id='QUOTE'> Originally posted by Lee@Nov 18 2004, 04:29 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:10 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?
You have an equal chance by opting to open the other door.

You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW.
you missed the possibility of two goats being behind any door, nor the combinations of goat +BMW, or goat + goat + BMW [/b][/quote]
Thats true however that wasnt how i read the questions meaning ;)

Plus, we already know that behnd the door the host opened is 1 goat ;)

grimm
11-18-2004, 07:30 AM
and its all moot if the door the contestant opens contains a BMW;)

Winetalk.com
11-18-2004, 07:31 AM
Originally posted by Lee+Nov 18 2004, 07:29 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 07:29 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:10 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?
You have an equal chance by opting to open the other door.

You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW. [/b][/quote]
Lee,
you haven't answered my question which was:
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door?
3) the same chances by opening the other door?


even though you answered the _why_ question
(incorrectly, I might say)
;-)))

Winetalk.com
11-18-2004, 07:32 AM
Originally posted by grimm@Nov 18 2004, 07:31 AM
and its all moot if the door the contestant opens contains a BMW;)
grimm,
pay fucking attention,
contestant doesn't open shit!
he only INDICATES what he wants to be opened.

Lee
11-18-2004, 07:32 AM
Sorry thought i said you had an equal chance by opening the other door.

There are only 2 doors left, one of them contains a car.. the other doesnt ;)

Winetalk.com
11-18-2004, 07:33 AM
Originally posted by Lee+Nov 18 2004, 07:31 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 07:31 AM)</td></tr><tr><td id='QUOTE'> Originally posted by grimm@Nov 18 2004, 04:31 AM
Originally posted by Lee@Nov 18 2004, 04:29 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:10 AM
You are on TV show,
there are 3 doors,
behind 2 of them there is a goat,
behind one is new BMW

you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door.

Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

...and why?
You have an equal chance by opting to open the other door.

You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW.
you missed the possibility of two goats being behind any door, nor the combinations of goat +BMW, or goat + goat + BMW
Thats true however that wasnt how i read the questions meaning ;)

Plus, we already know that behnd the door the host opened is 1 goat ;) [/b][/quote]
Lee,
you missed nothing,
it's grimm wjho misses everything
;-))

..even though BOTH of you gave incorrect answers.
;-)))

Lee
11-18-2004, 07:34 AM
Actually you know what..

Thinking about it logically..

No matter what door you open you have a better chance..

Youll either win a car or not.. which is more than you have right now prior to the door being opened :)

Now what do i win? LOL

Winetalk.com
11-18-2004, 07:34 AM
Originally posted by Lee@Nov 18 2004, 07:33 AM
Sorry thought i said you had an equal chance by opening the other door.

There are only 2 doors left, one of them contains a car.. the other doesnt ;)
you did, but
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

#3, the answer you gave, is INCORRECT answer
;-))))

Lee
11-18-2004, 07:36 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:35 AM
#3, the answer you gave, is INCORRECT answer
;-))))
Well shit you could have broken it to me easier than that ;)

Winetalk.com
11-18-2004, 07:36 AM
Originally posted by Lee@Nov 18 2004, 07:35 AM
Actually you know what..

Thinking about it logically..

No matter what door you open you have a better chance..

Youll either win a car or not.. which is more than you have right now prior to the door being opened :)

Now what do i win? LOL
you win NADA, zilch, fat ZERO....

all you have to do to win is to pick up the correct answer from
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?

and give the reasoning WHY
;-)
you now have only 2! correct answers left to chose from
;-)))

grimm
11-18-2004, 07:37 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct?

Lee
11-18-2004, 07:39 AM
Originally posted by grimm+Nov 18 2004, 04:38 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 04:38 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct? [/b][/quote]
Thats what i said didnt i? LOL

Winetalk.com
11-18-2004, 07:39 AM
Originally posted by grimm+Nov 18 2004, 07:38 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 07:38 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct? [/b][/quote]
grimm,
your logic is correct, but it doesn't give the answer to my question which was:
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?


which answer you think is correct, knowing from me that #3 is INCORRECT answer?

grimm
11-18-2004, 07:40 AM
shit someone beat me to it, but i explained my reasoning;)

when i get logic problems, i always shoot fr the simplest answer. if i cannot find a simple answer, my analytical side kicks in and i narrow it down to the simplest answer. this whole board was lucky i wasnt boiling it down to the LCD of every possibility:)

Winetalk.com
11-18-2004, 07:41 AM
Originally posted by Lee+Nov 18 2004, 07:40 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 07:40 AM)</td></tr><tr><td id='QUOTE'> Originally posted by grimm@Nov 18 2004, 04:38 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct?
Thats what i said didnt i? LOL [/b][/quote]
you did, but...I am looking for simple answer:
1)
2)
or
3)

and I can assure you,
3) is INCORRECT.

grimm
11-18-2004, 07:41 AM
Originally posted by Serge_Oprano+Nov 18 2004, 04:40 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 04:40 AM)</td></tr><tr><td id='QUOTE'> Originally posted by grimm@Nov 18 2004, 07:38 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct?
grimm,
your logic is correct, but it doesn't give the answer to my question which was:
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?


which answer you think is correct, knowing from me that #3 is INCORRECT answer? [/b][/quote]
oh better odds

66% rate of failure> 50%


so 1.

Winetalk.com
11-18-2004, 07:42 AM
Originally posted by grimm@Nov 18 2004, 07:41 AM
shit someone beat me to it, but i explained my reasoning;)

when i get logic problems, i always shoot fr the simplest answer. if i cannot find a simple answer, my analytical side kicks in and i narrow it down to the simplest answer. this whole board was lucky i wasnt boiling it down to the LCD of every possibility:)
yes, you BOTH beat each other to..INCORRECT CONCLUSION
;-))))

grimm
11-18-2004, 07:42 AM
yes i overthunk it:)

grimm
11-18-2004, 07:43 AM
and overcomplicated it:)

Winetalk.com
11-18-2004, 07:44 AM
Originally posted by grimm+Nov 18 2004, 07:42 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 07:42 AM)</td></tr><tr><td id='QUOTE'> Originally posted by Serge_Oprano@Nov 18 2004, 04:40 AM
Originally posted by grimm@Nov 18 2004, 07:38 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct?
grimm,
your logic is correct, but it doesn't give the answer to my question which was:
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?


which answer you think is correct, knowing from me that #3 is INCORRECT answer?
oh better odds

66% rate of failure> 50%


so 1. [/b][/quote]
BINGO!
we have a winner in WHICH possibility,
even though the answer to WHY is INCORRECT,
it doesn't support the 1) answer...
;-))

by your logic,
chosing new door or remain with your original choice gives the SAME 50-5- chance and this is WRONG conclusion and doesn't justify the opening of another door.

grimm
11-18-2004, 07:46 AM
Originally posted by grimm@Nov 18 2004, 04:19 AM


Say the door you opened was goatless, then it comes down to odds.

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take
serge, my first answer was sorta right, read the second paragraph if this was a logic not a trick question:)

so technically, i got it right the first time, then outhtought myself into the wrong answer by overcomplicating it, then thought back to the right answer

:)))))

Winetalk.com
11-18-2004, 07:47 AM
anybody cares to come up with plausable explanation WHY it's ALWAYS pays to chose the other door, after the host opened one of them?

Lee
11-18-2004, 07:48 AM
Haha i did the same thing Grimm went from 66%-50% but was concentrating on the wrong thing lol

Ah well it was a stupid question anyway and neither of won a new BMW or a goat ;)

Winetalk.com
11-18-2004, 07:49 AM
Originally posted by grimm+Nov 18 2004, 07:47 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 07:47 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-grimm@Nov 18 2004, 04:19 AM


Say the door you opened was goatless, then it comes down to odds.

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take
serge, my first answer was sorta right, read the second paragraph if this was a logic not a trick question:)

so technically, i got it right the first time, then outhtought myself into the wrong answer by overcomplicating it, then thought back to the right answer

:))))) [/b][/quote]
grimm,
your answer AND logic was incorrect and STILL is incorrect, because your chances of picking up the car by switching your original decission is NOT 50%...
it's 66%!!! probability to pick the car instead of goat when you switch!
;-))))

grimm
11-18-2004, 07:49 AM
Originally posted by Serge_Oprano+Nov 18 2004, 04:45 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 04:45 AM)</td></tr><tr><td id='QUOTE'> Originally posted by grimm@Nov 18 2004, 07:42 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:40 AM
Originally posted by grimm@Nov 18 2004, 07:38 AM
<!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:29 AM
Grimm,
I'll make it VERY simple:

door #1 has goat behind it,
door #2 has goat behind it,
door #3 has BMW behind it.
THIS you know.
What you don't know is:
which door is which.

and you did NOT open the door on the first try,
you only indicated which door you want to be opened,
IOW,
you don't know what's behind the door you have chosen!
oh ok, so she did not open the door, just indicated.

this is boolean algebra.

1 goat

1 BMW

2 Doors

initially she had a 1/3 shot. 66% rate of failure.

doh this is easy

her shot remains the same. nothing has changed. She still has 3 doors, two goats, one behind each door. and a BMW behind the third. so instead of it being a 66% rate of failure by remaining the same. so she keeps her pick, er odds of failure reduce to 50%. 1/2 instead of 1/3. all the host did was show 1/3 of her failure options.\

is that correct?
grimm,
your logic is correct, but it doesn't give the answer to my question which was:
Question:
do you have
1) better chances by opening the other door?
2) worse chances by opening the other door
3) the same chances by opening the other door?


which answer you think is correct, knowing from me that #3 is INCORRECT answer?
oh better odds

66% rate of failure> 50%


so 1.
BINGO!
we have a winner in WHICH possibility,
even though the answer to WHY is INCORRECT,
it doesn't support the 1) answer...
;-))

by your logic,
chosing new door or remain with your original choice gives the SAME 50-5- chance and this is WRONG conclusion and doesn't justify the opening of another door. [/b][/quote]
true. duh. jeez.


but 1 and 3 would be the same. so eithr answer is right.

how is one any less right than 3 if the end result is the same?

Winetalk.com
11-18-2004, 07:51 AM
Originally posted by grimm@Nov 18 2004, 07:50 AM


how is one any less right than 3 if the end result is the same?
very simple,
as I posted in my previous post,
the chances of winni9ng the car by switching your original choice is 66%,
not 50!!!!!!!!!!!!!!!!!

Lee
11-18-2004, 07:51 AM
Originally posted by Serge_Oprano+Nov 18 2004, 04:50 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 04:50 AM)</td></tr><tr><td id='QUOTE'> Originally posted by grimm@Nov 18 2004, 07:47 AM
<!--QuoteBegin-grimm@Nov 18 2004, 04:19 AM


Say the door you opened was goatless, then it comes down to odds.

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take
serge, my first answer was sorta right, read the second paragraph if this was a logic not a trick question:)

so technically, i got it right the first time, then outhtought myself into the wrong answer by overcomplicating it, then thought back to the right answer

:)))))
grimm,
your answer AND logic was incorrect and STILL is incorrect, because your chances of picking up the car by switching your original decission is NOT 50%...
it's 66%!!! probability to pick the car instead of goat when you switch!
;-)))) [/b][/quote]
Okay how do you figure that out?

If there are 3 doors and one has already been opened you wont choose that door.

1 goat
1 car

2 doors

50% chance of picking the right one when i went to school :huh:

Winetalk.com
11-18-2004, 07:53 AM
Originally posted by Lee+Nov 18 2004, 07:52 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 07:52 AM)</td></tr><tr><td id='QUOTE'> Originally posted by Serge_Oprano@Nov 18 2004, 04:50 AM
Originally posted by grimm@Nov 18 2004, 07:47 AM
<!--QuoteBegin-grimm@Nov 18 2004, 04:19 AM


Say the door you opened was goatless, then it comes down to odds.

the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip.

at least thats my take
serge, my first answer was sorta right, read the second paragraph if this was a logic not a trick question:)

so technically, i got it right the first time, then outhtought myself into the wrong answer by overcomplicating it, then thought back to the right answer

:)))))
grimm,
your answer AND logic was incorrect and STILL is incorrect, because your chances of picking up the car by switching your original decission is NOT 50%...
it's 66%!!! probability to pick the car instead of goat when you switch!
;-))))
Okay how do you figure that out?

If there are 3 doors and one has already been opened you wont choose that door.

1 goat
1 car

2 doors

50% chance of picking the right one when i went to school :huh: [/b][/quote]
Lee,
as I already explained to grimm 3 times only,
you have NOT opened the door,
you ONLY INDICATED which door you want to be opened.

Lee
11-18-2004, 07:55 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:54 AM
Lee,
as I already explained to grimm 3 times only,
you have NOT opened the door,
you ONLY INDICATED which door you want to be opened.
I get that i only indicated but if one of the 3 doors has already been opened that only leaves 2 doors to open.

With 2 possible scenarios..

Door 1 - Goat
Door 2 - Car

I think im gonna head to bed and figure this out when i wake up again lol

grimm
11-18-2004, 07:56 AM
Originally posted by Serge_Oprano@Nov 18 2004, 04:50 AM
grimm,
your answer AND logic was incorrect and STILL is incorrect, because your chances of picking up the car by switching your original decission is NOT 50%...
it's 66%!!! probability to pick the car instead of goat when you switch!
;-))))
this makes no sense. your probability of picking the goat would not stay the same.

instead of 1/3 doors, you have elimiated 1 door, making the new choice 1/2, or 50/50.


You are correct this far.from a mathematical perspective, it would remain constant, since it is still the original problem we are trying to solve. there could be three open doors, and the odds would still be 1/3 for the BMW.

but when you added a personal choice to it,it became a human Logic problem, and logic dictates fluid thinking, and when the third door was open, the logic problem changed. obviously the contestant seeing the goat, would shift the way she thought about the problem. She would not see it as 1/3 she would see it as 1/2 with one door being eliminated. the calculator would see it as 1/3:)

Winetalk.com
11-18-2004, 07:57 AM
Originally posted by Lee+Nov 18 2004, 07:56 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 07:56 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:54 AM
Lee,
as I already explained to grimm 3 times only,
you have NOT opened the door,
you ONLY INDICATED which door you want to be opened.
I get that i only indicated but if one of the 3 doors has already been opened that only leaves 2 doors to open.

With 2 possible scenarios..

Door 1 - Goat
Door 2 - Car

I think im gonna head to bed and figure this out when i wake up again lol [/b][/quote]
good idea!
I did exactly that, woke up,
read the correct answer and fully understand now WHY switching gets 66% chance and not 50 or 33%
;-)))

grimm
11-18-2004, 07:57 AM
Originally posted by Lee+Nov 18 2004, 04:56 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 04:56 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:54 AM
Lee,
as I already explained to grimm 3 times only,
you have NOT opened the door,
you ONLY INDICATED which door you want to be opened.
I get that i only indicated but if one of the 3 doors has already been opened that only leaves 2 doors to open.

With 2 possible scenarios..

Door 1 - Goat
Door 2 - Car

I think im gonna head to bed and figure this out when i wake up again lol [/b][/quote]
it was ony once, and not explained in the question:)

Winetalk.com
11-18-2004, 08:03 AM
Originally posted by grimm+Nov 18 2004, 07:57 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 07:57 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Serge_Oprano@Nov 18 2004, 04:50 AM
grimm,
your answer AND logic was incorrect and STILL is incorrect, because your chances of picking up the car by switching your original decission is NOT 50%...
it's 66%!!! probability to pick the car instead of goat when you switch!
;-))))
this makes no sense. your probability of picking the goat would not stay the same.

instead of 1/3 doors, you have elimiated 1 door, making the new choice 1/2, or 50/50.


You are correct this far.from a mathematical perspective, it would remain constant, since it is still the original problem we are trying to solve. there could be three open doors, and the odds would still be 1/3 for the BMW.

but when you added a personal choice to it,it became a human Logic problem, and logic dictates fluid thinking, and when the third door was open, the logic problem changed. obviously the contestant seeing the goat, would shift the way she thought about the problem. She would not see it as 1/3 she would see it as 1/2 with one door being eliminated. the calculator would see it as 1/3:) [/b][/quote]
grimm,
I could have easily pick a $100 from you by betting you,
but I won't, because you are a good sport and I am SURE you'll see WHY your logic failed,
and YES, this is a VERY hard problem to solve, because the wrong answer is sooooooo obvious!
;-))

Here are the arguments in favor of 1)

When you are presented with the choice of 3 doors,
what are the possible outcomes:

1) you pick BMW
2) you pick goat
3) you pick goat


66% chance that you were wrong on your first original pick,
2 out of 3.
Therefore,
CHANGING your door choice, will lead to positive outcome 2 out of 3 times.

Does it make sence NOW why switching is more beneficial than staying with original choice and NOT equal to 50%????
;-))

Winetalk.com
11-18-2004, 08:06 AM
..and if you are still not convinced...
imagine 100! doors instead of 3
(logic for 100 doors is the SAME as for 3 or 3,000,000 doors)

you indicated one door and the host opened 98 doors and...
would you assume that you picked the car in 1:100 chance or the other one closed is where BMW is?
;-))))

Lee
11-18-2004, 08:06 AM
Oh yeah and.. im stealing this question to ask on GWW lol

grimm
11-18-2004, 08:07 AM
Originally posted by Serge_Oprano+Nov 18 2004, 04:52 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 04:52 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-grimm@Nov 18 2004, 07:50 AM


how is one any less right than 3 if the end result is the same?
very simple,
as I posted in my previous post,
the chances of winni9ng the car by switching your original choice is 66%,
not 50!!!!!!!!!!!!!!!!! [/b][/quote]
the answer is probably that by switching doors, you extracate yourself from the 2/3 problem, into a whole new logic problem that puts you at 1/2.

so instead of 1/3 shot, you would have a 1/2 shot. its the elimination that is the key. logic dictates that if can readuce your odds by making the switch you should.

an easier way to look at it for me was, what if there were 10 doors, and one by one the tv host opens them, revealing nothing. he stops when he gets to two. your original odds were 1-10, those are still your odds. switching doors would make it 1/2, a more probable shot.


and to think, no math involved

grimm
11-18-2004, 08:08 AM
yes i see where my logic failed, i forgot the #1 rule of logic problems, make the set bigger than it is, much easier to see lines on a football field than sistine chapel on the head of a pin.:)

Winetalk.com
11-18-2004, 08:09 AM
Originally posted by grimm+Nov 18 2004, 08:08 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (grimm @ Nov 18 2004, 08:08 AM)</td></tr><tr><td id='QUOTE'> Originally posted by Serge_Oprano@Nov 18 2004, 04:52 AM
<!--QuoteBegin-grimm@Nov 18 2004, 07:50 AM


how is one any less right than 3 if the end result is the same?
very simple,
as I posted in my previous post,
the chances of winni9ng the car by switching your original choice is 66%,
not 50!!!!!!!!!!!!!!!!!
the answer is probably that by switching doors, you extracate yourself from the 2/3 problem, into a whole new logic problem that puts you at 1/2.

so instead of 1/3 shot, you would have a 1/2 shot. its the elimination that is the key. logic dictates that if can readuce your odds by making the switch you should.

an easier way to look at it for me was, what if there were 10 doors, and one by one the tv host opens them, revealing nothing. he stops when he gets to two. your original odds were 1-10, those are still your odds. switching doors would make it 1/2, a more probable shot.


and to think, no math involved [/b][/quote]
very good,
you are now leaning in the right direction except..
if there were 10 doors,
your odds of winning the car on switch would have been...
90%!
;-))))

grimm
11-18-2004, 08:10 AM
and yep, you could have snaked 100 bucks off of me there:) my mind works too fast at times.. sometimes the answer is right in front of you:)

Winetalk.com
11-18-2004, 08:10 AM
Originally posted by grimm@Nov 18 2004, 08:09 AM
yes i see where my logic failed, i forgot the #1 rule of logic problems, make the set bigger than it is, much easier to see lines on a football field than sistine chapel on the head of a pin.:)
hahahah,
good analogy but..
you WERE leaning in the right direction, by bringing 10 doors instead of 3 example
;-)))

Winetalk.com
11-18-2004, 08:10 AM
Originally posted by Lee@Nov 18 2004, 08:07 AM
Oh yeah and.. im stealing this question to ask on GWW lol
pay us royalties, mofo!!!!
;-))))

Winetalk.com
11-18-2004, 08:11 AM
Originally posted by grimm@Nov 18 2004, 08:11 AM
and yep, you could have snaked 100 bucks off of me there:) my mind works too fast at times.. sometimes the answer is right in front of you:)
after snaking over 1/4 of a mil of you,
I can afford leaving you the last $100
;-))))

grimm
11-18-2004, 08:12 AM
yep 9/10, not 1/2:)


indeed, expanding it to ten made the answer obvious. i just ten as an arbitrary number, easy to work with.

grimm
11-18-2004, 08:14 AM
Originally posted by Serge_Oprano+Nov 18 2004, 05:12 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 05:12 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-grimm@Nov 18 2004, 08:11 AM
and yep, you could have snaked 100 bucks off of me there:) my mind works too fast at times.. sometimes the answer is right in front of you:)
after snaking over 1/4 of a mil of you,
I can afford leaving you the last $100
;-)))) [/b][/quote]
i wasnt complaining, its all about the bottom line.:).

grimm
11-18-2004, 08:14 AM
and you need to add some zeros to that 100:)

Winetalk.com
11-18-2004, 08:16 AM
Originally posted by grimm@Nov 18 2004, 08:15 AM
and you need to add some zeros to that 100:)
I won't,
I pretend it never happened
;-))))

Winetalk.com
11-18-2004, 08:20 AM
Originally posted by Lee@Nov 18 2004, 08:07 AM
Oh yeah and.. im stealing this question to ask on GWW lol
thou shall not steal
;))))


http://forums.gaywidewebmasters.com/showth...49205#post49205 (http://forums.gaywidewebmasters.com/showthread.php?s=&postid=49205#post49205)

;-))))

Lee
11-18-2004, 08:21 AM
Originally posted by Serge_Oprano+Nov 18 2004, 05:21 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Serge_Oprano @ Nov 18 2004, 05:21 AM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Lee@Nov 18 2004, 08:07 AM
Oh yeah and.. im stealing this question to ask on GWW lol
thou shall not steal
;))))


http://forums.gaywidewebmasters.com/showth...49205#post49205 (http://forums.gaywidewebmasters.com/showthread.php?s=&postid=49205#post49205)

;-)))) [/b][/quote]
Haha.

Now im not going to know how many smart guys we have on GWW although i know we have 99% more than on the zoo ;)

Winetalk.com
11-18-2004, 08:23 AM
Originally posted by Lee+Nov 18 2004, 08:22 AM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 08:22 AM)</td></tr><tr><td id='QUOTE'> Originally posted by Serge_Oprano@Nov 18 2004, 05:21 AM
<!--QuoteBegin-Lee@Nov 18 2004, 08:07 AM
Oh yeah and.. im stealing this question to ask on GWW lol
thou shall not steal
;))))


http://forums.gaywidewebmasters.com/showth...49205#post49205 (http://forums.gaywidewebmasters.com/showthread.php?s=&postid=49205#post49205)

;-))))
Haha.

Now im not going to know how many smart guys we have on GWW although i know we have 99% more than on the zoo ;) [/b][/quote]
Lee,
but the true question is:
can your 99% smarter guys find Afganistan on the map??????


Smart bombs could....
;-))))

Lee
11-18-2004, 08:24 AM
You know, to be honest, i dont htink i could even find it on a map :(

Im not all that good with geography, i only got a D grade for that subject :(

grimm
11-18-2004, 08:24 AM
Just give them Schroedinger's Cat and let them chew on that:)

DrGuile
11-18-2004, 10:36 AM
as soon as 1 goat door is open, your probability of having picked the right door originally become 1/2, if you pick again, they stay 1/2... (wow, imagine that, probabilities do change)


if the question was: Are the probability better at the time of the second pick than when you made your first pick, than yes, sure....



but a logic problem being tricky only because of how the question is asked isnt much fun... especially when its a russian asking ;)

Winetalk.com
11-18-2004, 10:56 AM
you still don't get it, do you?
;-))

I am sorry it takes Canadiens longer to comprehend things than to the normal people
;-)))

Dravyk
11-18-2004, 02:24 PM
Ok, there are two goats. One is heading south down I-66 at 140 miles per hour with a 20 mile an hour head wind. Another goat is going north along I-228 at 162 miles an hour with a 41 mile an hour tail wind. Which goat is wearing the beret?

Lee
11-18-2004, 02:54 PM
Originally posted by Dravyk@Nov 18 2004, 11:25 AM
Ok, there are two goats. One is heading south down I-66 at 140 miles per hour with a 20 mile an hour head wind. Another goat is going north along I-228 at 162 miles an hour with a 41 mile an hour tail wind. Which goat is wearing the beret?
The French one :lol:

Dravyk
11-18-2004, 03:01 PM
Originally posted by Lee+Nov 18 2004, 02:55 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 02:55 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Dravyk@Nov 18 2004, 11:25 AM
Ok, there are two goats. One is heading south down I-66 at 140 miles per hour with a 20 mile an hour head wind. Another goat is going north along I-228 at 162 miles an hour with a 41 mile an hour tail wind. Which goat is wearing the beret?
The French one :lol: [/b][/quote]
Close! Very close! But it's a trick question. :P

sarettah
11-18-2004, 03:15 PM
Originally posted by grimm@Nov 18 2004, 08:25 AM
Just give them Schroedinger's Cat and let them chew on that:)
I'd rather ponder Zeller Schwarze Kat myself :okthumb:

Almighty Colin
11-18-2004, 03:18 PM
This is a famous problem. The answer is so annoyingly counterintuitive that mathematicians were writing Marilyn Savant to tell her she had the answer wrong in her column (she had it right). It also took Paul Erdos, one of the best mathematicians of the 20th century a little while before he agreed with the solution after he gave the wrong answer.

Lee
11-18-2004, 03:35 PM
Originally posted by Dravyk+Nov 18 2004, 12:02 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Dravyk @ Nov 18 2004, 12:02 PM)</td></tr><tr><td id='QUOTE'> Originally posted by Lee@Nov 18 2004, 02:55 PM
<!--QuoteBegin-Dravyk@Nov 18 2004, 11:25 AM
Ok, there are two goats. One is heading south down I-66 at 140 miles per hour with a 20 mile an hour head wind. Another goat is going north along I-228 at 162 miles an hour with a 41 mile an hour tail wind. Which goat is wearing the beret?
The French one :lol:
Close! Very close! But it's a trick question. :P [/b][/quote]
Oh in that case..

The one that surrendered ;)

sarettah
11-18-2004, 03:47 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?

Nickatilynx
11-18-2004, 03:55 PM
Originally posted by Serge_Oprano@Nov 18 2004, 07:57 AM
you still don't get it, do you?
;-))

I am sorry it takes Canadiens longer to comprehend things than to the normal people
;-)))
Bullshit!!!!

The correct answer is:

You bribe the stagehand to signal you which door has the car behind.

Why gamble?


;-))

Lee
11-18-2004, 04:11 PM
Originally posted by sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
30 minutes.

You dont say whether they all have to get onto the other side or just 'cross' the bridge ;)

sarettah
11-18-2004, 04:14 PM
Originally posted by Lee+Nov 18 2004, 04:12 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 04:12 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
30 minutes.

You dont say whether they all have to get onto the other side or just 'cross' the bridge ;) [/b][/quote]
to the other side smart ass................. and by the rules.....

also you have to be able to explain the way you got the answer too......

Same rules the 7th graders had.


btw, how do you cross the bridge without getting to the other side ?

Lee
11-18-2004, 04:25 PM
Originally posted by sarettah+Nov 18 2004, 01:15 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (sarettah @ Nov 18 2004, 01:15 PM)</td></tr><tr><td id='QUOTE'> Originally posted by Lee@Nov 18 2004, 04:12 PM
<!--QuoteBegin-sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
30 minutes.

You dont say whether they all have to get onto the other side or just 'cross' the bridge ;)
to the other side smart ass................. and by the rules.....

also you have to be able to explain the way you got the answer too......

Same rules the 7th graders had.


btw, how do you cross the bridge without getting to the other side ? [/b][/quote]
'all' get to the other side..

You could have all four of them cross the bridge once and have 3 on one side and 1 on the other ;)

sarettah
11-18-2004, 05:43 PM
Originally posted by Lee+Nov 18 2004, 04:26 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 04:26 PM)</td></tr><tr><td id='QUOTE'> Originally posted by sarettah@Nov 18 2004, 01:15 PM
Originally posted by Lee@Nov 18 2004, 04:12 PM
<!--QuoteBegin-sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
30 minutes.

You dont say whether they all have to get onto the other side or just 'cross' the bridge ;)
to the other side smart ass................. and by the rules.....

also you have to be able to explain the way you got the answer too......

Same rules the 7th graders had.


btw, how do you cross the bridge without getting to the other side ?
'all' get to the other side..

You could have all four of them cross the bridge once and have 3 on one side and 1 on the other ;) [/b][/quote]
Nopers...

Lantern has to make it back some how. They cannot go across without the lantern and there is only one lantern.

:nyanya:

edited in: besides, by my reckoning, your solution would still result in at least 40 minutes, not 30 even if the lantern ended up on one side with 3 on one side and the forth on the other..

But the problem needs them to all end up together on the opposite side of the ravine and they all have to use the bridge to get across.

metzo
11-18-2004, 06:41 PM
Originally posted by sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
The least amount of time for all 4 men to get across the bridge would be 1 hour and 5 minutes...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 1 and Man 3 go across - 20 mins
Man 1 goes back - 5 mins
Man 1 and Man 4 go across - 25 mins

sarettah
11-18-2004, 06:48 PM
Originally posted by metzo+Nov 18 2004, 06:42 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (metzo @ Nov 18 2004, 06:42 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
The least amount of time for all 4 men to get across the bridge would be 1 hour and 5 minutes...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 1 and Man 3 go across - 20 mins
Man 1 goes back - 5 mins
Man 1 and Man 4 go across - 25 mins [/b][/quote]
Close but WRONG...

:nyanya:

metzo
11-18-2004, 06:58 PM
Originally posted by sarettah+Nov 18 2004, 03:49 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (sarettah @ Nov 18 2004, 03:49 PM)</td></tr><tr><td id='QUOTE'> Originally posted by metzo@Nov 18 2004, 06:42 PM
<!--QuoteBegin-sarettah@Nov 18 2004, 12:48 PM
Heres one for you that my daughter and I played with the other night:

Scenario: Pitch black night. 4 men are traveling with one lantern amongst them. They come to a bridge across a very deep ravine. The bridge is only wide enough and strong enough to support 2 of the men at a time. There is no railing or side on the bridge so because of the darkness you cannot go over the bridge without the lantern and furthermore no man dares to go across the bridge without being in actual contact with the lantern.

Man 1 can cross the bridge in 5 minutes
Man 2 can cross the bridge in 10 minutes
Man 3 can cross the bridge in 20 minutes
Man 4 can cross the bridge in 25 minutes

What is the least amount of time that it can take for all 4 men to cross the bridge ?
The least amount of time for all 4 men to get across the bridge would be 1 hour and 5 minutes...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 1 and Man 3 go across - 20 mins
Man 1 goes back - 5 mins
Man 1 and Man 4 go across - 25 mins
Close but WRONG...

:nyanya: [/b][/quote]
sneaky...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 3 and Man 4 go across - 25 mins
Man 2 goes back - 10 mins
Man 1 and Man 2 go across - 10 mins

a la 1 hour

go canada! :rokk:

Nickatilynx
11-18-2004, 07:03 PM
sigh..

1 and 2 cross over 10 mins
1 returns 5mins
3 and 4 cross 25mins
2 returns 10 mins
1 and 2 cross 10 mins

60 mins.....

sarettah
11-18-2004, 07:04 PM
Originally posted by metzo@Nov 18 2004, 06:59 PM
sneaky...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 3 and Man 4 go across - 25 mins
Man 2 goes back - 10 mins
Man 1 and Man 2 go across - 10 mins

a la 1 hour

go canada! :rokk:
Give the man a ceeeeegar....

you probably googled it though :nyanya:

(j/k)

Nickatilynx
11-18-2004, 07:04 PM
shit beaten by metzo by a hair!!


feck!

;-))

sarettah
11-18-2004, 07:05 PM
Originally posted by Nickatilynx@Nov 18 2004, 07:04 PM
sigh..

1 and 2 cross over 10 mins
1 returns 5mins
3 and 4 cross 25mins
2 returns 10 mins
1 and 2 cross 10 mins

60 mins.....
Well, it's always easier to get after someone posts the answer.... :nyanya:

metzo
11-18-2004, 07:06 PM
Originally posted by sarettah+Nov 18 2004, 04:05 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (sarettah @ Nov 18 2004, 04:05 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-metzo@Nov 18 2004, 06:59 PM
sneaky...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 3 and Man 4 go across - 25 mins
Man 2 goes back - 10 mins
Man 1 and Man 2 go across - 10 mins

a la 1 hour

go canada! :rokk:
Give the man a ceeeeegar....

you probably googled it though :nyanya:

(j/k) [/b][/quote]
If I googled it, wouldn't I have just done it the first time? ;-)

sarettah
11-18-2004, 07:08 PM
Originally posted by metzo+Nov 18 2004, 07:07 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (metzo @ Nov 18 2004, 07:07 PM)</td></tr><tr><td id='QUOTE'> Originally posted by sarettah@Nov 18 2004, 04:05 PM
<!--QuoteBegin-metzo@Nov 18 2004, 06:59 PM
sneaky...

Man 1 goes across with Man 2 - 10 mins
Man 1 goes back with the lantern - 5 mins
Man 3 and Man 4 go across - 25 mins
Man 2 goes back - 10 mins
Man 1 and Man 2 go across - 10 mins

a la 1 hour

go canada! :rokk:
Give the man a ceeeeegar....

you probably googled it though :nyanya:

(j/k)
If I googled it, wouldn't I have just done it the first time? ;-) [/b][/quote]
Actually, a good cheater would google it, then post the wrong answer, then come up with the right answer....

At least thats the way I do...err...I mean thats how friends of mine do it.... :yowsa:

Nickatilynx
11-18-2004, 07:09 PM
Try this test to see if you have what it takes to be a British Army Officer :)...ok except prolly nationality :) (http://www.army.mod.uk/careers/officer/the_challenge.html)

sarettah
11-18-2004, 07:14 PM
Originally posted by Nickatilynx@Nov 18 2004, 07:10 PM
Try this test to see if you have what it takes to be a British Army Officer :)...ok except prolly nationality :) (http://www.army.mod.uk/careers/officer/the_challenge.html)
I don't have to take the test, I am not qualified to be a Britis Officer because:

1. I am not pasty faced
2. I don't like my meat boiled
3. I am not gay

:okthumb:

Nickatilynx
11-18-2004, 07:18 PM
Originally posted by sarettah+Nov 18 2004, 04:15 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (sarettah @ Nov 18 2004, 04:15 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin-Nickatilynx@Nov 18 2004, 07:10 PM
Try this test to see if you have what it takes to be a British Army Officer :)...ok except prolly nationality :) (http://www.army.mod.uk/careers/officer/the_challenge.html)
I don't have to take the test, I am not qualified to be a Britis Officer because:

1. I am not pasty faced
2. I don't like my meat boiled
3. I am not gay

:okthumb: [/b][/quote]
You don't have to be gay to be a Brit Army Officer!!!
















OK, sure , to be promoted to Major or above it DOES help if you are...

sarettah
11-18-2004, 07:29 PM
Battery went dead
Diabetic is in a coma
Burned the hell out of the pilot
Lit the entire desert on fire
Nomads killed my fitnesss instructor guy
But, I did manage to shoot down the rescue helicopter :okthumb:

Nickatilynx
11-18-2004, 07:30 PM
Fuck!!!!

You are right!!


Question 14 )
You are in command of a squadron of Challenger main battle tanks.
You are fully armed and fueled.
Your orders are to engage all enemy


When faced by a vastly superior force in entrenched positions with full armour and air support do you:

i) retreat
ii) attack
iii) surrender
iv) utilising the bright pink camo paint on yr tanks , infiltrate the enemy and once won over hurt their feelings by criticising there uniforms , decor or taste in TV programming


Answer

i) we are not Italian!!!
ii) only if they are soccer fans , chanting of "come over here if you reckon your hard enough" should establish this.
iii) We aren't fucking French
iv) Correct answer, after the enemy feelings have been hurt however , make them a nice cup of tea and say "Oh well , never mind then , it'll all come out in the wash"


;-)))

Nickatilynx
11-18-2004, 07:31 PM
Originally posted by sarettah@Nov 18 2004, 04:30 PM
Battery went dead
Diabetic is in a coma
Burned the hell out of the pilot
Lit the entire desert on fire
Nomads killed my fitnesss instructor guy
But, I did manage to shoot down the rescue helicopter :okthumb:
ahahahahaha sweeet :)

Congrats Osama :)

Lisa
11-18-2004, 07:33 PM
British Army clearly has high standards...I got 30/80, had no battery power and the diabetic chick was in a coma...but I have all the attributes to make it as an officer.

:D

Nickatilynx
11-18-2004, 07:40 PM
I got...

""78 out of 80.
We fixed the plane .
The pilot won a Olympic Medal in Cycling
The chick with diabetes is alive and married to an Insurance Salesman in Des Moines.She is into the BDSM scene.
Haliburton built a Casino in the Desert
And the nomads , now known as "San de Nigga and the Infidels" , had a platinum album called "Nuke it!"

Welcome back General , two points deducted , forgot to make tea"



:)

Dravyk
11-18-2004, 08:01 PM
Originally posted by Lee+Nov 18 2004, 03:36 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Lee @ Nov 18 2004, 03:36 PM)</td></tr><tr><td id='QUOTE'> Originally posted by Dravyk@Nov 18 2004, 12:02 PM
Originally posted by Lee@Nov 18 2004, 02:55 PM
<!--QuoteBegin-Dravyk@Nov 18 2004, 11:25 AM
Ok, there are two goats. One is heading south down I-66 at 140 miles per hour with a 20 mile an hour head wind. Another goat is going north along I-228 at 162 miles an hour with a 41 mile an hour tail wind. Which goat is wearing the beret?
The French one :lol:
Close! Very close! But it's a trick question. :P
Oh in that case..

The one that surrendered ;) [/b][/quote]
It's the French Canadien goat! B)

Lee
11-18-2004, 08:43 PM
Originally posted by Nickatilynx@Nov 18 2004, 04:19 PM
You don't have to be gay to be a Brit Army Officer!!!
But it helps LOL